Bài tập 1 trang 127 SGK Hình học 12 NC

A.  \(2\).                        B.  \(4\).

C.  \(0\).                        D.  \(3\)

A.  \(12\).                      B.  \(14\).

C.  \(10\).                      D.  \(13\).

A.  \(2{a^3}\).              

B.  \(\frac{{{a^3}}}{2} \cdot \)

C.  \(\frac{{{a^3}}}{6} \cdot \)                      

D.  \(\frac{{2{a^3}}}{3}\)

A.  \(R = \frac{{4V}}{S}\).           B.  \(R = \frac{V}{{3S}}\)

C.  \(R = \frac{{3V}}{S}\).           D.  \(R = \frac{S}{{3V}}\)

A.  \({\left( {x - 1} \right)^2} + {\left( {y - 1} \right)^2} + {\left( {z + 2} \right)^2} = 9.\)

B.  \({\left( {x - 1} \right)^2} + {\left( {y - 1} \right)^2} + {\left( {z + 2} \right)^2} = 36.\)

C.  \({\left( {x - 1} \right)^2} + {\left( {y - 1} \right)^2} + {\left( {z + 2} \right)^2} = 3.\)

D.  \({\left( {x + 1} \right)^2} + {\left( {y + 1} \right)^2} + {\left( {z - 2} \right)^2} = 9.\)

A.  \(60^\circ .\)             B.  \(45^\circ .\)

C.  \(30^\circ .\)             D.  \(90^\circ .\)

A.\(\frac{x}{c} + \frac{y}{b} + \frac{z}{a} = 1\)

B. \(\frac{x}{b} + \frac{y}{a} + \frac{z}{c} = 1\)

C. \(\frac{x}{a} + \frac{y}{c} + \frac{z}{b} = 1\)

D. \(\frac{x}{a} + \frac{y}{b} + \frac{z}{c} = 1\)

A. 0.                                       B. 6.

C. 5.                                       D. 2.

A. \(B\left( {0;2\sqrt 2 ;0} \right),C\left( {0;0;2\sqrt 2 } \right).\)

B. \(B\left( {0;4;0} \right),C\left( {0;0;4} \right).\)

C. \(B\left( {0;2\sqrt 6 ;0} \right),C\left( {0;0;2\sqrt 6 } \right).\)

D. \(B\left( {0;16;0} \right),C\left( {0;0;16} \right).\)

A. \(\frac{{115}}{3}{{\rm{m}}^2}.\)  B. \(\frac{{120}}{3}{{\rm{m}}^2}.\)

C. \(\frac{{110}}{3}{{\rm{m}}^2}.\)  D. \(\frac{{112}}{3}{{\rm{m}}^2}.\)

A. \(\left\{ \begin{array}{l}x = t\\y = 0\\z = 0.\end{array} \right.\)

B. \(\left\{ \begin{array}{l}x = 2 - t\\y = t\\z = 4 - t.\end{array} \right.\)

C. \(\left\{ \begin{array}{l}x = 3 + t\\y =  - t\\z = 3.\end{array} \right.\)

D. \(\left\{ \begin{array}{l}x = 0\\y = t\\z = 6.\end{array} \right.\)

A. \(\frac{x}{2} = \frac{{y + 3}}{4} = \frac{z}{3} \cdot \)

B. \(\frac{{x - 2}}{2} = \frac{{y - 1}}{1} = \frac{{z - 3}}{3} \cdot \)

C. \(\frac{{x - 2}}{2} = \frac{{y - 1}}{3} = \frac{{z - 3}}{2} \cdot \)

D. \(\frac{x}{2} = \frac{{y + 3}}{3} = \frac{z}{2} \cdot \)