Bài tập 10 trang 144 SGK Giải tích 12

A. 1                              

B. \(\sqrt {13} \)    

C. 5                              

D. 13

A. \({z_1} = 3 + 4i\,,\,\,{z_2} =  - 4 - 3i\).

B. \({z_1} = 4 + 3i\,,\,\,{z_2} =  - 3 - 4i\).

C. \({z_1} =  - 4 - 3i\,,\,\,{z_2} = 3 + 4i\)

D. \({z_1} = \left( {2\sqrt 3  + 1} \right) + 2\sqrt 3 \) \({z_2} = \left( { - 2\sqrt 3  + 1} \right) - 2\sqrt 3 i\)

A. \( - 10\sqrt {377} \).                       

B. \(10\sqrt {377} \).

C. \(7\sqrt {377} \).                           

D. \( - 3\sqrt {377} \).

A. \({\left( {x - 2} \right)^2} + {\left( {y - 1} \right)^2} = 1\). 

B. \({\left( {x + 2} \right)^2} + {\left( {y - 1} \right)^2} = 1\).

C. \({\left( {x - 2} \right)^2} + {\left( {y - 2} \right)^2} = 1\).  

D. \({\left( {x + 2} \right)^2} + {\left( {y + 1} \right)^2} = 1\)

A. \(\left[ \begin{array}{l}z = 2\sqrt 5  + i\sqrt 5 \\z =  - 2\sqrt 5  - i\sqrt 5 \end{array} \right.\).    

B. \(\left[ \begin{array}{l}z =  - 2\sqrt 5  + i\sqrt 5 \\z = 2\sqrt 5  - i\sqrt 5 \end{array} \right.\).

C. \(\left[ \begin{array}{l}z = \sqrt 5  + 2\sqrt 5 i\\z =  - \sqrt 5  - 2\sqrt 5 i\end{array} \right.\).   

D. \(\left[ \begin{array}{l}z =  - \sqrt 5  + 2\sqrt 5 i\\z = \sqrt 5  - 2\sqrt 5 i\end{array} \right.\).

A. \(S = \{  - 1;\,\dfrac{{2 \pm i\sqrt 3 }}{2}\} \). 

B. \(S = \{  - 1\} \).

C. \(S = \{  - 1;\dfrac{{5 \pm i\sqrt 3 }}{4}\} \). 

D. \(S = \{  - 1;\dfrac{{1 \pm i\sqrt 3 }}{2}\} \).

A. 2    

B. 4    

C. 10          

D. \(\sqrt {10} \)