Bài tập 8.2 trang 20 SBT Toán 6 Tập 2

\(\begin{array}{l}
\left( A \right)\frac{1}{2} + \frac{3}{{16}} + \frac{1}{{16}}\\
 = \frac{8}{{16}} + \frac{3}{{16}} + \frac{1}{{16}}\\
 = \frac{{12}}{{16}} = \frac{3}{4}\\
\left( B \right)\frac{1}{4} + \frac{1}{8} + \frac{3}{{16}}\\
 = \frac{4}{{16}} + \frac{2}{{16}} + \frac{3}{{16}}\\
 = \frac{9}{{16}}\\
\left( C \right)\frac{1}{4} + \frac{5}{8} + \frac{1}{{16}}\\
 = \frac{4}{{16}} + \frac{{10}}{{16}} + \frac{1}{{16}}\\
 = \frac{{15}}{{16}}\\
\left( D \right)\frac{1}{4} + \frac{1}{8} + \frac{5}{{16}}\\
 = \frac{4}{{16}} + \frac{2}{{16}} + \frac{5}{{16}}\\
 = \frac{{11}}{{16}}
\end{array}\)

Chọn đáp án A

-- Mod Toán 6 HỌC247