QUẢNG CÁO
Câu hỏi trắc nghiệm (10 câu):
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- A. \(\overrightarrow {AM} \)
- B. \(\overrightarrow {PB} \)
- C. \(\overrightarrow {AP} \)
- D. \(\overrightarrow {MN} \)
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- A. \(\left| {\overrightarrow {AB} + \overrightarrow {AC} } \right| = a\sqrt 2 \)
- B. \(\left| {\overrightarrow {AB} + \overrightarrow {AC} } \right| = \frac{{a\sqrt 2 }}{2}\)
- C. \(\left| {\overrightarrow {AB} + \overrightarrow {AC} } \right| = 2a\)
- D. \(\left| {\overrightarrow {AB} + \overrightarrow {AC} } \right| = a\)
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- A. \(\left| {\overrightarrow {CA} + \overrightarrow {AB} } \right| = 2\)
- B. \(\left| {\overrightarrow {CA} + \overrightarrow {AB} } \right| = 2\sqrt {13} \)
- C. \(\left| {\overrightarrow {CA} + \overrightarrow {AB} } \right| = 5\)
- D. \(\left| {\overrightarrow {CA} + \overrightarrow {AB} } \right| = \sqrt {13} \)
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- A. \(\left| {\overrightarrow {OB} + \overrightarrow {OC} } \right| = a\)
- B. \(\left| {\overrightarrow {OB} + \overrightarrow {OC} } \right| = a\sqrt 2 \)
- C. \(\left| {\overrightarrow {OB} + \overrightarrow {OC} } \right| = \frac{a}{2}\)
- D. \(\left| {\overrightarrow {OB} + \overrightarrow {OC} } \right| = \frac{{a\sqrt 2 }}{2}\)
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- A. \(\overrightarrow {OA} + \overrightarrow {OC} + \overrightarrow {OE} = \vec 0\)
- B. \(\overrightarrow {BC} + \overrightarrow {FE} = \overrightarrow {AD} \)
- C. \(\overrightarrow {OA} + \overrightarrow {OB} + \overrightarrow {OC} = \overrightarrow {EB} \)
- D. \(\overrightarrow {AB} + \overrightarrow {CD} + \overrightarrow {FE} = \vec 0\)
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- A. \(a\)
- B. \(\sqrt 2 a\)
- C. \(\frac{a}{2}\)
- D. \(2a\)
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- A. \(\overrightarrow {AB} + \overrightarrow {CD} + \overrightarrow {EF} = \overrightarrow {AF} + \overrightarrow {ED} + \overrightarrow {BC} \)
- B. \(\overrightarrow {AB} + \overrightarrow {CD} + \overrightarrow {EF} = \overrightarrow {AF} + \overrightarrow {ED} + \overrightarrow {CB} \)
- C. \(\overrightarrow {AE} + \overrightarrow {BF} + \overrightarrow {DC} = \overrightarrow {DF} + \overrightarrow {BE} + \overrightarrow {AC} \)
- D. \(\overrightarrow {AC} + \overrightarrow {BD} + \overrightarrow {EF} = \overrightarrow {AD} + \overrightarrow {BF} + \overrightarrow {EC} \)
-
- A. 2
- B. 4
- C. 8
- D. \(2\sqrt 3 \)
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- A. \(\overrightarrow {BC} + \overrightarrow {AB} \)
- B. \( - \overrightarrow {OA} + \overrightarrow {OC} \)
- C. \(\overrightarrow {BA} + \overrightarrow {DA} \)
- D. \(\overrightarrow {DC} - \overrightarrow {CB} \)
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- A. \(\overrightarrow {AC} = \overrightarrow {BD} \)
- B. \(\overrightarrow {AB} + \overrightarrow {AC} + \overrightarrow {AD} = \vec 0\)
- C. \(\left| {\overrightarrow {AB} - \overrightarrow {AD} } \right| = \left| {\overrightarrow {AB} + \overrightarrow {AD} } \right|\)
- D. \(\left| {\overrightarrow {BC} + \overrightarrow {BD} } \right| = \left| {\overrightarrow {AC} - \overrightarrow {AB} } \right|\)
ADMICRO
ADMICRO
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