Bài tập 5.127 trang 218 SBT Toán 11

A. \(\left[ { - \sqrt 3 ;\sqrt 3 } \right]\)

B. \(\left[ { - \dfrac{1}{{\sqrt 3 }};\dfrac{1}{{\sqrt 3 }}} \right]\)

C. \(\left( { - \infty ; - \sqrt 3 } \right] \cup \left[ {\sqrt 3 ; + \infty } \right)\)

D. \(\left( { - \infty ; - \dfrac{1}{{\sqrt 3 }}} \right] \cup \left[ {\dfrac{1}{{\sqrt 3 }}; + \infty } \right)\)

A. \(x = \dfrac{1}{8}\)  

B. \(x = \sqrt {\dfrac{1}{8}} \)

C. \(x = \dfrac{1}{{64}}\) 

D. \(x =  - \dfrac{1}{{64}}\)

A. \(\left\{ { - 1;2} \right\}\)   

B. \(\left\{ { - 1;3} \right\}\)

C. \(\left\{ {0;4} \right\}\)    

D. \(\left\{ {1;2} \right\}\)

A. \(\dfrac{{2{x^2} + 10x + 9}}{{{{({x^2} + 3x + 3)}^2}}}\)

B. \(\dfrac{{ - 2{x^2} - 10x - 9}}{{{{({x^2} + 3x + 3)}^2}}}\)

C. \(\dfrac{{{x^2} - 2x - 9}}{{{{({x^2} + 3x + 3)}^2}}}\)

D. \(\dfrac{{ - 2{x^2} - 5x - 9}}{{{{({x^2} + 3x + 3)}^2}}}\)

\(A. y' = 3{({x^2} + 5x + 6)^3} + 2(x + 3){(x + 2)^3}\)

\(B. y' = 2{({x^2} + 5x + 6)^2} + 3(x + 3){(x + 2)^3}\)

\(C. y' = 3({x^2} + 5x + 6) + 2(x + 3)(x + 2)\)

\(D. y' = 3{({x^2} + 5x + 6)^2} + 2(x + 3){(x + 2)^3}\)

A. \(y' = 5{(1 - {x^3})^4}\)

B. \(y' =  - 15{x^2}{(1 - {x^3})^4}\)

C. \(y' =  - 3{(1 - {x^3})^4}\)

D. \(y' =  - 5{(1 - {x^3})^4}\)

A. 0   

B. 1  

C. 2

D. Không tồn tại