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Câu 1: Tìm GTLN và GTNN của A = x2 - x + 1

Câu 1: Tìm GTLN và GTNN của A = x2 - x + 1

Câu 2: Giải pt

a) 2 https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_. x- 1 + 2 https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_. x + 1 - 2x2 +2 https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_. x2 -1 = 0

b) 2xhttps:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_. x + 2 + 2https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_. x -2 = x2 +4 https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_. x2 - 4

Câu 3 : Cho tam giác ABC, AB < AC, BD là phân giác, CE là đường cao.

a) Cm tam giác ABD đồng dạng ACE

b) tam giác ADE đồng dạng ABC

c) Tia DE cắt CB tại I. Cm tam giác IBE đồng dạng IDC

d) Gọi O là trug điểm của BC. Cm ID . IE = OI2 - OC2

Câu 4: Cho tam giác ABC vuông tại A. Đường cao AH

a) Cm tam giác AHB đồng dạng CHA

b) Kẻ phân giác AD của tam giác CHA và BK của tam giác ABC ( D thuộc AC, K thuộc AC) . BK cắt AH ở E, cắt AD ở F. Cm tam giác AEF đồng dạng BEH

c) Chứng minh KD song song AH

d) Cm EH https:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_. AD = KDhttps:https://hoc247.net/image/faq/data2/216985_.https://hoc247.net/image/faq/data2/216985_.hoc247.nethttps://hoc247.net/image/faq/data2/216985_.imagehttps://hoc247.net/image/faq/data2/216985_.faqhttps://hoc247.net/image/faq/data2/216985_.data2https://hoc247.net/image/faq/data2/216985_.563596_. BC

  bởi thu hảo 25/08/2018
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Câu trả lời (1)

  • Bài 1: \(A=x^2-x+1\)

    \(=x^2+\dfrac{1}{2}x+\dfrac{1}{2}x+\dfrac{1}{2}-\dfrac{1}{2}-\dfrac{1}{4}+1\)

    \(=x\left(x+\dfrac{1}{2}\right)+\dfrac{1}{2}\left(x+\dfrac{1}{2}\right)-\dfrac{3}{4}\)

    \(=\left(x+\dfrac{1}{2}\right)\left(x+\dfrac{1}{2}\right)+\dfrac{3}{4}\)

    \(=\left(x+\dfrac{1}{2}\right)^2+\dfrac{3}{4}\)

    => \(\left(x+\dfrac{1}{2}\right)^2+\dfrac{3}{4}>\dfrac{3}{4}\)

    Vậy GTNN của biểu thức \(A\)\(\dfrac{3}{4}\)

      bởi ngothimy linh 27/06/2018
    Like (0) Báo cáo sai phạm

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