Phương trình 

\(\begin{array}{l} \Leftrightarrow \frac{1}{2}\sin 2x + \frac{{\sqrt 3 }}{2}\cos 2x = \frac{{\sqrt 3 }}{2}\\ \Leftrightarrow \sin \left( {2x + \frac{\pi }{3}} \right) = \frac{{\sqrt 3 }}{2}\\ \Leftrightarrow \sin \left( {2x + \frac{\pi }{3}} \right) = \sin \frac{\pi }{3}\\ \Leftrightarrow \left[ \begin{array}{l} 2x + \frac{\pi }{3} = \frac{\pi }{3} + k2\pi \\ 2x + \frac{\pi }{3} = \pi - \frac{\pi }{3} + k2\pi \end{array} \right.\\ \Leftrightarrow \left[ \begin{array}{l} x = k\pi \\ x = \frac{\pi }{6} + k\pi \end{array} \right.,{\rm{ }}k \in Z \end{array}\)

- \(0<\frac{\pi }{6}+k\pi <\frac{\pi }{2}\Leftrightarrow -\frac{1}{6}\)