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  • Câu hỏi:

    Xà phòng hóa hoàn toàn 17,6 gam CH3COOC2H5 trong dung dịch NaOH (vừa đủ), thu được dung dịch chứa m gam muối. Giá trị của m là:

    CH3COOC2H5 + NaOH → CH3COONa + C2H5OH
    ⇒ \(n_{CH_{3}COONa} = n_{CH_{3}COOC_{2}H_{5}} = 0,2 \ mol\)
    ⇒ mmuối = 16,4g

    Hãy trả lời câu hỏi trước khi xem đáp án và lời giải
    ADMICRO/
 
 

 

 
 

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