Ta có \(A = \dfrac{{\left( {3\dfrac{2}{{15}} + \dfrac{1}{5}} \right):2\dfrac{1}{2}}}{{\left( {5\dfrac{3}{7} - 2\dfrac{1}{4}} \right):4\dfrac{{43}}{{56}}}}\)\(= \dfrac{{\left( {\dfrac{{47}}{{15}} + \dfrac{3}{{15}}} \right):\dfrac{5}{2}}}{{\left( {\dfrac{{38}}{7} - \dfrac{9}{4}} \right):\dfrac{{267}}{{56}}}} = \dfrac{{\dfrac{{50}}{{15}}.\dfrac{2}{5}}}{{\left( {\dfrac{{152}}{{28}} - \dfrac{{63}}{{28}}} \right).\dfrac{{56}}{{267}}}}\)​​= \(\dfrac{{\dfrac{4}{3}}}{{\dfrac{{89}}{{28}}.\dfrac{{56}}{{267}}}} = \dfrac{{\dfrac{4}{3}}}{{\dfrac{2}{3}}} = 2\)

Và \(B = \dfrac{{1,2:\left( {1\dfrac{1}{5}.1\dfrac{1}{4}} \right)}}{{0,32 + \dfrac{2}{{25}}}}\)​\(= \dfrac{{\dfrac{6}{5}:\left( {\dfrac{6}{5}.\dfrac{5}{4}} \right)}}{{\dfrac{8}{{25}} + \dfrac{2}{{25}}}} = \dfrac{{\dfrac{6}{5}:\dfrac{3}{2}}}{{\dfrac{{10}}{{25}}}} = \dfrac{{\dfrac{4}{5}}}{{\dfrac{2}{5}}} = 2\)

Vậy A = B