Giải bài 7.2 trang 18 SBT KHTN 6 Chân trời sáng tạo - CTST

\(\begin{array}{l} A.K = t\left( {^0C} \right) - 273\\ B.K = t\left( {^0C} \right) + 273\\ C.K = \frac{{t\left( {^0C} \right) + 273}}{2}\\ D.K = 2.t\left( {^0C} \right) + 273 \end{array}\)

\(\begin{array}{l} A{.^0}C = \frac{5}{9}\left( {t\left( {^0F} \right) + 32} \right)\\ B{.^0}C = \frac{9}{5}\left( {t\left( {^0F} \right) - 32} \right)\\ C{.^0}C = \frac{5}{9}\left( {t\left( {^0F} \right) - 32} \right)\\ D{.^0}C = \frac{9}{5}\left( {t\left( {^0F} \right) + 32} \right) \end{array}\)