Đặt A có CTĐGN là: C_xH_yO_zN_t

_{\(\begin{align} & x\text{ }:\text{ }y\text{ }:\text{ }z\text{ }:\text{ }t\text{ }=\frac{51,3%}{12}:\frac{9,4%}{1}:\frac{27,3%}{16}:\frac{12%}{14} \\ & =\text{ }4,28\text{ }:\text{ }9,40\text{ }:\text{ }1,71\text{ }:\text{ }0,86 \\ & \to ~~x\text{ }:\text{ }y\text{ }:\text{ }z\text{ }:\text{ }t\text{ }=\text{ }5\text{ }:\text{ }11\text{ }:\text{ }2\text{ }:\text{ }1 \\ & \to \text{ }CTGN\text{ }của\text{ }X\text{ }l\grave{a}:\text{ }{{C}_{5}}{{H}_{11}}{{O}_{2}}N \\ & \frac{{{M}_{A}}}{{{M}_{KK}}}=4,03\to \text{ }{{M}_{A}}~=\text{ }4,03.29\text{ }=\text{ }117\text{ }\left( g/mol \right) \\ & \to ~CTPT\text{ }của\text{ }X\text{ }l\grave{a}\text{ }:\text{ }{{C}_{5}}{{H}_{11}}{{O}_{2}}N \\ \end{align} \)}